Re: Drop leading zeros in a variable

<> wrote in message
news:fd5319c6-7c35-4f27-aeac-...
> I'm using a variable that is a random hex number in my batch file. I'm
> using this value to search some registry keys, but the registry keys
> don't use the leading zeros. So, I'm looking for a way to drop only
> the leading zeros in my variable.
>
> It's always an 8 character value and could contain up to 7 zeros. I
> can do:
>
> set VAR=%VAR:0=%
>
> ...but this drops all zeros instead of just the leading zeros. So if
> my VAR=00110010, I would just want to drop the leading two zeros so my
> result would be VAR=110010. If my VAR=0000000A, I'd want to drop all 7
> leading zeros with an end result of VAR=A.
>
> It's also valid to have all zeros for this number, so in that case, I
> would want to drop all zeros leaving VAR undefined.
>
> Any pointers would be greatly appreciated.

Not particularly elegant but it works . . .
@echo off
set x=0000012345
:Loop
set x= %x: 0=%
if [%x:~0,2%]==[ 0] goto Loop
set x=%x:~1%
echo x=%x%

"Pegasus (MVP)" <> wrote in message
news:%...
>
> <> wrote in message
> news:fd5319c6-7c35-4f27-aeac-...
>> I'm using a variable that is a random hex number in my batch file. I'm
>> using this value to search some registry keys, but the registry keys
>> don't use the leading zeros. So, I'm looking for a way to drop only
>> the leading zeros in my variable.
>>
>> It's always an 8 character value and could contain up to 7 zeros. I
>> can do:
>>
>> set VAR=%VAR:0=%
>>
>> ...but this drops all zeros instead of just the leading zeros. So if
>> my VAR=00110010, I would just want to drop the leading two zeros so my
>> result would be VAR=110010. If my VAR=0000000A, I'd want to drop all 7
>> leading zeros with an end result of VAR=A.
>>
>> It's also valid to have all zeros for this number, so in that case, I
>> would want to drop all zeros leaving VAR undefined.
>>
>> Any pointers would be greatly appreciated.
>
> Not particularly elegant but it works . . .
> @echo off
> set x=0000012345
> :Loop
> set x= %x: 0=%
> if [%x:~0,2%]==[ 0] goto Loop
> set x=%x:~1%
> echo x=%x%

Here's another inelegant solution:

@echo off

set _in=00004006

set _out=\%_in%
set _out=%_out:\0=\%
set _out=%_out:\0=\%
set _out=%_out:\0=\%
set _out=%_out:\0=\%
set _out=%_out:\0=\%
set _out=%_out:\0=\%
set _out=%_out:\0=\%
set _out=%_out:\=%
echo/"%_in%" - "%_out%"

/Al

"Al Dunbar" wrote:

>
> "Pegasus (MVP)" <> wrote in message
> news:%...
> >
> > <> wrote in message
> > news:fd5319c6-7c35-4f27-aeac-...
> >> I'm using a variable that is a random hex number in my batch file. I'm
> >> using this value to search some registry keys, but the registry keys
> >> don't use the leading zeros. So, I'm looking for a way to drop only
> >> the leading zeros in my variable.
> >>
> >> It's always an 8 character value and could contain up to 7 zeros. I
> >> can do:
> >>
> >> set VAR=%VAR:0=%
> >>
> >> ...but this drops all zeros instead of just the leading zeros. So if
> >> my VAR=00110010, I would just want to drop the leading two zeros so my
> >> result would be VAR=110010. If my VAR=0000000A, I'd want to drop all 7
> >> leading zeros with an end result of VAR=A.
> >>
> >> It's also valid to have all zeros for this number, so in that case, I
> >> would want to drop all zeros leaving VAR undefined.
> >>
> >> Any pointers would be greatly appreciated.
> >
> > Not particularly elegant but it works . . .
> > @echo off
> > set x=0000012345
> > :Loop
> > set x= %x: 0=%
> > if [%x:~0,2%]==[ 0] goto Loop
> > set x=%x:~1%
> > echo x=%x%
>
> Here's another inelegant solution:
>
> @echo off
>
> set _in=00004006
>
> set _out=\%_in%
> set _out=%_out:\0=\%
> set _out=%_out:\0=\%
> set _out=%_out:\0=\%
> set _out=%_out:\0=\%
> set _out=%_out:\0=\%
> set _out=%_out:\0=\%
> set _out=%_out:\0=\%
> set _out=%_out:\=%
> echo/"%_in%" - "%_out%"
>
> /Al
>

Or,

@echo off

set "in#=00 00 B 1234050"

Set "out#=%in#%" you could replace all spaces here (optional).
:TrimLeadingZeros from out#

If "%out#:~0,1%"=="0" (
Set "out#=%out#:~1%"
Goto:TrimLeadingZeros)

:: Left Trim
If "%out#:~0,1%"==" " (
Set "out#=%out#:~1%"
Goto:TrimLeadingZeros)

echo/%in#% =^> %out#%

pause>nul


\Rems

"Tom Lavedas" <> wrote in message
news:cd9b0c9b-da4f-4bd6-9c0d-...
On Feb 13, 2:25 pm, \RemS <R...@discussions.microsoft.com> wrote:
> "Al Dunbar" wrote:
>
> > "Pegasus (MVP)" <I....@fly.com.oz> wrote in message
> >news:%...
>
> > > <jnton...@gmail.com> wrote in message
> > >news:fd5319c6-7c35-4f27-aeac-...
> > >> I'm using a variable that is a random hex number in my batch file.
> > >> I'm
> > >> using this value to search some registry keys, but the registry keys
> > >> don't use the leading zeros. So, I'm looking for a way to drop only
> > >> the leading zeros in my variable.
>
> > >> It's always an 8 character value and could contain up to 7 zeros. I
> > >> can do:
>
> > >> set VAR=%VAR:0=%
>
> > >> ...but this drops all zeros instead of just the leading zeros. So if
> > >> my VAR=00110010, I would just want to drop the leading two zeros so
> > >> my
> > >> result would be VAR=110010. If my VAR=0000000A, I'd want to drop all
> > >> 7
> > >> leading zeros with an end result of VAR=A.
>
> > >> It's also valid to have all zeros for this number, so in that case, I
> > >> would want to drop all zeros leaving VAR undefined.
>
> > >> Any pointers would be greatly appreciated.
>
> > > Not particularly elegant but it works . . .
> > > @echo off
> > > set x=0000012345
> > > :Loop
> > > set x= %x: 0=%
> > > if [%x:~0,2%]==[ 0] goto Loop
> > > set x=%x:~1%
> > > echo x=%x%
>
> > Here's another inelegant solution:
>
> > @echo off
>
> > set _in=00004006
>
> > set _out=\%_in%
> > set _out=%_out:\0=\%
> > set _out=%_out:\0=\%
> > set _out=%_out:\0=\%
> > set _out=%_out:\0=\%
> > set _out=%_out:\0=\%
> > set _out=%_out:\0=\%
> > set _out=%_out:\0=\%
> > set _out=%_out:\=%
> > echo/"%_in%" - "%_out%"
>
> > /Al
>
> Or,
>
> @echo off
>
> set "in#=00 00 B 1234050"
>
> Set "out#=%in#%" you could replace all spaces here (optional).
> :TrimLeadingZeros from out#
>
> If "%out#:~0,1%"=="0" (
> Set "out#=%out#:~1%"
> Goto:TrimLeadingZeros)
>
> :: Left Trim
> If "%out#:~0,1%"==" " (
> Set "out#=%out#:~1%"
> Goto:TrimLeadingZeros)
>
> echo/%in#% =^> %out#%
>
> pause>nul
>
> \Rems

Here's my offering ...

@echo off
set "x=%~1"
:loop
if [%x:~0,1%]==[0] (set x=%x:~1% & goto :loop)
echo %x%

Tom Lavedas
==========

==> and the award for the simplest and most straightforward solution goes
to...

/Al