You've got the same misunderstanding - that apparently missing 0.8GB of
memory address space is memory space that reserved by the operating system
for running hardware installed in your computer. The same 0.8GB memory
addresses cannot also be used for RAM at the same time but it does
constitute a portion of the 4GB total memory that Vista 32bit can access
(4GB maximum memory, not 4GB RAM memory +another 0.8GB memory for hardware).
See also:
http://members.cox.net/slatteryt/RAM.html
"Luis Armelin" <> wrote in message
news:...
> Tony,
> You are right....
> I have a ASUS motherboard with 4GB installed, and my Windows Vista
> Ultimate SP1 display that I have 4GB on system propriety. But it isn't
> true, because on BIOS, i can see that I have 4GB and the system will use
> just 3.2GB.
>
>
> "RalfG" <> escreveu na mensagem
> news:4E9E9E97-CB82-4504-9B38-...
>>
>> "tony" <> wrote in message
>> news:N5dTl.214806$2...
>>> Yet again, a major rewrite of Vista and still no support for 4Gb ram as
>>> was promised in pre-release of Vista blurb years ago.....
>>> Tony
>>
>> You're just misunderstanding the situation. A 32 Bit OS can only access a
>> maximum of 4GB memory. Vista 32bit version can access a maximum of 4Gb of
>> memory too but that memory does not equate to only user RAM. A portion
>> of that total memory space is required for all the assorted hardware
>> installed in the computer, including graphics card memory. The amount
>> required can vary from system to system. IOW any memory space required by
>> the hardware (eg. 512MB installed on a video card) takes up a portion of
>> the total 4Gbytes of memory that Vista can access and only the remainder
>> that is left over can be used for RAM memory. With 4GB of RAM installed
>> and a 128MB video card you might be able to use 3.2 to 3.5 GB of the RAM
>> but if you put in a graphics card or SLI combo with 1GB of video memory
>> your usable RAM would be reduced to something less than 3GB.
>
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