ISA, OWA, and Trend CSM Dashboard

Discussion in 'Windows Small Business Server' started by SusanV, Jan 30, 2007.

  1. SusanV

    SusanV Guest

    Good morning all,

    Getting ready to bring my new SBS 2003 R2 server live and really struggling
    here to get things working and not really getting anywhere. I have one
    client, and the server is connected to the internet using a non-published IP
    address for testing (for short periods of time only, as this is NOT secure
    with ISA turned off or misconfigured). I run the internet connection wizard
    and disable the firewall and the client can access OWA and Remote server
    management. Turn the firewall on (again via the wizard) and the client has
    internet access, but no OWA - immediate login timeout without ever getting
    the logon page. Same for remote server management. And basically I can just
    forget about Trend's security dashboard - I'm not getting in there at all,
    proxy error due to port being 4343. Found an article to use Security
    Explorer, but that won't run? At any rate, clients not being able to hit OWA
    internally tells me something's very wrong here to begin with.

    Also, I'm occasionally getting errors that lock up the app when accessing
    various tabs in ISA management console property sheets, so I'm figuring
    perhaps I need to reinstall ISA, but before I do that I figured I'd give
    folks out there a holler and ask for some advice, as ISA is a mystery to me
    and I'm really not sure what I may have done wrong during the original
    install - there were no errors.

    TIA,

    SusanV
     
    SusanV, Jan 30, 2007
    #1
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  2. SusanV

    SusanV Guest

    BTW, the "one client" is in this lab environment - once we go live I'll have
    27 clients in 2 subnets - another piece to the puzzle - Do I have to
    configure anything in DNS or ISA to define the other subnet? The server is
    in the 192.168.0.x subnet (as is my test client), and we have another
    location using IP scheme of 192.168.1.x, DCHP has both ranges defined.

    Thanks again,

    SusanV
     
    SusanV, Jan 30, 2007
    #2
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